
Arturo O. answered 05/24/17
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Over a time interval [t1, t2], the average speed <v> is given by
<v> = [s(t2) - s(t1)] / (t2 - t1)
You are given
s(t) = -19t2 + 57t
and several time intervals [t1, t2]. Just plug in the time values of the ends of the time intervals and compute the average speed using the formula above for <v>. These are all worked the same. In problem (d), you will end up with an average speed as a function of h.

Arturo O.
Here is what I get for (d):
s(1 + h) = -19(1 + h)2 + 57(1 + h) = -19(1 + 2h + h2) + 57 + 57h
= 38 + 19h - 19h2
s(1) = -19(1)2 + 57(1) = 38
s(1 + h) - s(1) = 38 + 19h - 19h2 - 38 = -19h2 + 19h = 19h(-h + 1)
(1 + h) - 1 = h
<v> = 19h(-h + 1) / h = 19(-h + 1)
Does this help?
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05/24/17
Hailey H.
05/24/17