find the vertex and the axis of​ symmetry,

Question

Given the quadratic function f(x) = -2x^2 + 6x + 3

a. Find the vertex

b. Find the axis of symmetry

c. Find the x- and y-intercepts

d. State the domain and range of the function

e. Find the interval(s) over which the function is increasing f. Find the interval(s) over which the function is decreasing g. Graph the function

Answer 1

a)  The x coordinate of the vertex is x = -b/2a where b =6 and a =-2. X=-6/-6 =1. To find the y-coordinate plug x=1 into the equation and compute the y. B) x=-b/2a C) y-intercept =c=3; x intercepts use the quadratic formula x = (-b+- sqrt(b^2-4ac))/2a D) domain is all real numbers; range is y coordinate of vertexrom b to negative infinity E) increasing form negative infinity to x coordinate of vertex from a. Decreasing from x coordinate of vertex to plus infinity div>