graph g(x)= 4 + log_2x

Question

 g(x)= 4 + log_2x

or

g(x)= 4 + log base2 x

 

1. Graph the function

2. Plot at least two points on the graph. e form or fraction form?

3. Draw all asymptotes  = x=0 Draw verticle asymptote through 0. Correct?

 

Thank You All !!

 

 

Answer 1

If g(x) = 4 + log₂x, we can also express this as y = 4 + log₂x

 

y - 4 = log₂x

 

2^{(y - 4)} = x in exponential form. This function can never equal 0, and it can never be negative. The y-axis serves as a vertical asymptote. The y-axis is the vertical line x = 0.

 

In fraction form, it could be written as 2^y/2⁴ = x

 

If y = 4, then x = 1

If y = 5, then x = 2

 

Two points on the graph are (1, 4) and (2, 5)