(1/4)^x=8^x-1 (1/2^-x=1.6 3^x/2+1=12.2 log3(7x)=log3(2x+0.5) log5x-log(15.5)=2 logx-log(x/100)=x 5-3^x=-40 9^2y=66 log2x+logx=11 3logx-log6+log2.4=9 2^x/3=80 3/28/2014 | Sierra from Champion, PA | 1 Answer | 0 Votes Mark favorite Subscribe Comment
(1/4)^x = 8^(x - 1) (2^(-2))^x = (2^3)^(x - 1) 2^(-2x) = 2^(3x - 3) -2x = 3x - 3 -5x = -3 x = 3/5 ===== log(x) - log(x/100) = x log(x/(x/100)) = x 10^x = x/(x/100) = 100 x / x = 10^2 x = 2 ===== log(2x) + log(x) = 11 log(2x^2) = 11 10^11 = 2x^2 x^2 = 5(10^10) x = ± √(5) (10^5) 3/28/2014 | Steve S. Comment