On a number line, put a circle at x = 3/2 to indicate that 3/2 is not in the solution set, then darken in all values of x < 3/2.
You can write the inequality, by factoring out 3x2, as follows
3x2(2x-3)<0 by inspection the roots are x=0 and x=3/2. so for x<0 the inequality is satisfied because 2x-3 <0 when x<0 and the inequality is satisfied when 0<x<3/2. When x>3/2 the function is positive so the inequality is not satisfied.