Inactive Tutor answered 03/28/14
Cyn' C.
asked 03/28/146x^3 - 9x^2<0
6x3 - 9x2 <0
Solving for all values of x.
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3 Answers By Expert Tutors
Tutor
New to Wyzant
6x^3 - 9x^2 < 0
6x^2(x - 3/2) < 0
Left side has zeros at 0 and 3/2.
Left side is negative when x ≠ 0 and x < 3/2;
i.e., x ∈ (–∞,0) U (0,3/2).
6x3 - 9x2 < 0
3x2(2x - 3) < 0
The 3x2 term is always positive, so we must have:
(2x - 3) < 0
2x < 3
x < 3/2
On a number line, put a circle at x = 3/2 to indicate that 3/2 is not in the solution set, then darken in all values of x < 3/2.
Hi Cyn',
You can write the inequality, by factoring out 3x2, as follows
3x2(2x-3)<0 by inspection the roots are x=0 and x=3/2. so for x<0 the inequality is satisfied because 2x-3 <0 when x<0 and the inequality is satisfied when 0<x<3/2. When x>3/2 the function is positive so the inequality is not satisfied.
Jim
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Inactive Tutor
03/28/14