Lines perpendicular to y=3/2+11

Question

I need the answer to this problem.

Answer 1

Hi Caleb,

 

Is your equation y = (3/2)x+11?

 

If you are asking for the equation of a line perpendicular to this line, you need to provide at least one point it passes through. With the given information, I only can definitively tell you that the line perpendicular to  y = (3/2)x+11 will have a slope of -2/3 because when two lines are perpendicular, their slopes have this relationship:

m₁ = -1/m₂  where m1 and m2 are the slopes of the lines, respectively.