
Steve S. answered 03/26/14
Tutor
5
(3)
Tutoring in Precalculus, Trig, and Differential Calculus
P(t) = (25t^2 + 125t + 200)/(t^2 + 5t + 40)
P(0) = (25(0)^2 + 125(0) + 200)/((0)^2 + 5(0) + 40)
P(0) =200/40 = 20/4 = 5 thousand
as t → ∞,
P(t) = (25 + 125/t + 200/t^2)/(1 + 5/t + 40/t^2)
→ (25+0+0)/(1+0+0) = 25 thousand.