Three consecutive integers such that two times the second is 6 more than three times the third

Question

Three consecutive integers such that two times the second is 6 more then three times the third

Answer 1

The integers are

 

1st: n

2nd: n + 1

3rd: n + 2

 

The words in the problem statement translate into

 

2(n + 1) = 3(n + 2) + 6

 

Solve for n.

 

2n + 2 = 3n + 12

 

n = -10

n + 1 = -9

n + 2 = -8

 

Test the solutions.