factorise. x(x³-y³)+3xy(x-y) =???

Question

Sir plz.. ....explain me.. ....

Thank u

Answer 1

The first term has a difference of cubes:

 

(x³ - y³) = (x - y)(x² + xy + y²)

 

 

We can factor the whole thing out as

 

x(x - y)(x² + xy + y²) + 3xy(x - y)

 

 

The common factor of the two terms is  x(x - y).

 

x(x - y)[(x² + xy + y²) + 3y] =

 

x(x - y)(x² + xy + y² + 3y)