Patrick D. answered 04/16/17
Tutor
5
(10)
Patrick the Math Doctor
X = green or yellow marble
The probability of selecting the needed can is 1/2
CAN #1 Can #2 Probability of winning
0 rrXXXX 1/2*1/3 = 1/6 = 16.6666666666...%
X rr XXX 1/2*2/5 = 1/5 = 20%
The probability of selecting the needed can is 1/2
CAN #1 Can #2 Probability of winning
0 rrXXXX 1/2*1/3 = 1/6 = 16.6666666666...%
X rr XXX 1/2*2/5 = 1/5 = 20%
XX rr XX 1/2*1/2 = 1/4 = 25%
XXX rr X 1/2* 2/3 = 1/3 = 33.33333...%
XXXX rr 1/2 = 50%
r rXXXX 1/2*1 + 1/2*1/5 = 6/10 = 3/5 = 60%
rX rXXX 1/2*1/2 + 1/2*1/4 = 1/4 + 1/8 = 3/8 = 37.5%
rXX rXX 1/2*1/3 + 1/2*1/3 = 1/3 = 33.33333....
rXXX rX 1/2*1/4 + 1/2*1/2 = 1/8 + 1/4 = 3/8 = 37.5%
rXXXX r 1/2*1/5 + 1/2 = 1/10 + 1/2 = 6/10 = 3/5 = 60%
rr XXXX same as 1st case
XXXX rr 1/2 = 50%
r rXXXX 1/2*1 + 1/2*1/5 = 6/10 = 3/5 = 60%
rX rXXX 1/2*1/2 + 1/2*1/4 = 1/4 + 1/8 = 3/8 = 37.5%
rXX rXX 1/2*1/3 + 1/2*1/3 = 1/3 = 33.33333....
rXXX rX 1/2*1/4 + 1/2*1/2 = 1/8 + 1/4 = 3/8 = 37.5%
rXXXX r 1/2*1/5 + 1/2 = 1/10 + 1/2 = 6/10 = 3/5 = 60%
rr XXXX same as 1st case
CONCLUSION:
1 can contains a single red marble, other can contains the other 5 marbles.