The length of a rectangle is 5 ft less than twice the width, and the area of the rectangle is 52 ft2 . Find the dimensions of the rectangle.

Question

The length of a rectangle is
5 ft
less than twice the width, and the area of the rectangle is
52 ft2
. Find the dimensions of the rectangle.

Answer 1

Suppose width of a rectangle =w  ft

                     length = (2w-5) ft

 

Area of a rectangle= Length*Width

                    52= (2w-5)*w

                    52= 2w² -5w

                 2w² -5w -52=0

                 2w² -13w+8w-52=0

                  w(2w-13)+4(2w-13)=0

                    (2w-13)(w+4)=0

   2w-13= 0     or   w+4=0

    w=13/2=6.5      or w=-4   which is not possible.

width = 6.5 ft, length=2w-5 =13-5=8 ft