Michael J. answered 04/05/17
Tutor
5
(5)
Understanding the Principles and Basics with Analysis
1)
Divide both sides of the equation 2.
(10)3x = 24
Log both sides of the equation and bring down any exponent as the coefficient of the log.
3xLog(10) = Log(24)
Note that Log(10) is 1.
3x = log(24)
2)
Add 2 to both sides of the equation.
42x = -11
Log both sides of the equation and bring down any exponent as the coefficient of the log.
2xLog(4) = Log(-11)
This one has no solution, since the argument of a log cannot be negative.
SECOND:
1)
We can rewrite -8 as -log3(6561).
-log3(6561) + log(3x + 5)2 = 2
Log3[(3x + 5)2 / 6561] = Log3(9)
Equate arguments.
(3x + 5)2 / 6561 = 9
Now you can solve for x. I leave this part to you.
Michael J.
38 = 6561
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04/05/17
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04/05/17