
Patrick D. answered 04/12/17
Tutor
5
(10)
Patrick the Math Doctor
Oh Jennifer
Note that g(x) = 2X + 7
a) f(g(x)) = 3 [ 2X + 7 ]^2 - 5
= 3 [ 4x^2 + 28 X + 49]- 5
= 12X^2 + 84X + 147 - 5
= 12X^2 + 84X + 142
b) g(f(x)) = 2( 3X^2 - 5) + 7
= 6x^2 - 10 + 7
= 6x^2 - 3
--------------------------------------
a) f + g = 2x2 - 4x + 8
b) f - g = 2X^2 - 10X - 8 , so at X=-2 the result is 2(-2)^2 - 10(-2) - 8 = 2*4 + 20 - 8 = 8 + 20 - 8 = 20
c) f*g = 6x^3 - 21x^2 + 16X^2 - 56X = 6X^3 - 5x^2 - 56x = x(6x^2 - 5X - 56)
so at X=-4, the result is -4( 6*(-4)^2 - 5(-4) - 56) =
-4( 6*(16) + 20 - 56) =
-4( 96 + 20 - 56) =
-4( 60) = -240
d) f/g = (2X^2-7X)/(3X+8) so for X=-1, the result is (2(-1)^2 - 7(-1)) / (3*-1 + 8)
= (2(1) + 7)/( -3 + 8) =
(2 +7)/(-3+8) = 9/5 = 1.4