Find five consecutive integers whose sum is 170

Question

Find five integers whose sum is 170. All steps included. Using VESA method

Answer 1

V (variable):

     Let x be the first consecutive integer.

     Then, the five consecutive integers are:  x, (x+1), (x+2), (x+3), (x+4)

 

E (Equation/Proportion):

    Translate:  "five consecutive integers whose sum is 170"

        x + (x+1) + (x+2) + (x+3) + (x+4)  =  170

 

S (solve):

        x + (x+1) + (x+2) + (x+3) + (x+4)  =  170

        5x + 10 = 170           [collect terms]

        5x = 160                    [subtract 10 from both sides]

         x = 32                    [divide both sides by 5]

    Then,

       x=32,  (x+1)=33,  (x+2)=34,  (x+3)=35,  (x+4)=36

    

A (Write your Answer in a complete sentence):

    The five consecutive integers whose sum is 170 are 32, 33, 34, 35, and 36.

Answer 2

Since they're consecutive numbers, assuming the first one be x. then next four numbers are x+1, x+2, x+3, x+4

now their sum is 170. therefore,

 

x+x+1+x+2+x+3+x+4=170

=>5x=170-10

=> 5x=160

=> x=32

so the first one 32. then you can find the other four numbers