Solving logarithms

Question

Use the properties of exponential and logarithmic functions to solve each system. 

Log(2x-y)=1 

 

log(x+y)=3Log2

Answer 1

log (2x - y) = 1

2x - y = 10

 

log (x + y) = 3 log 2

log (x + y) = log 8

log (x + y) - log 8 = 0

log [(x + y) / 8] = 0

1 = (x + y) / 8

 

Can you solve the system?