x+8/x^2-9 Domian

Question

Find the domian

Answer 1

Set the denominator equal to zero and solve for x.  The x value is your restriction.  Then the domain is all real numbers except for that value of x.

Answer 2

(x+8)/(x²-9)

 

Since we can't divide by zero the restriction is:

x²-9 = 0

x²=9

x = ±3

 

x can be any real number except -3 or 3

 

Domain is (-∞,-3)U(-3,3)U(3,∞)