
Sarah G.
asked 03/11/14Help ? Porfavor ? Gracias :)
Re write the exponentian equatiin in equivalent logarithmic form
1) e2 =7.389
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if possible write the expressions using sums and/or difference of logarithmic expressions that do not contain the logarithms of products, quotients, or powers
1) ln(x(7-x)3)
2) ln(xy2/z)
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2 Answers By Expert Tutors

Elana G. answered 03/11/14
Tutor
4.8
(39)
A Gator Can Chomp Away Your Accounting Fears
1) ln=log with a base of e, so
ln7.389=2
The exponent goes on the other side of the equal sign and the answer to the exponential equation goes after the ln or log.

Elana G.
2) When there is division within the log you break the expression into parts and subtract the expressions. When there is multiplication within the log expression you break the expression into parts and add the expressions.
ln(xy^2/z)
ln(xy^2)-ln(z)
ln(x)+ln(y^2)-ln(z)
With ln(y^2) you can move the power of 2 to the left of the expression, so
2ln(y)
So the final answer is
ln(x)+2ln(y)-ln(z)
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03/11/14

Steve S. answered 03/11/14
Tutor
5
(3)
Tutoring in Precalculus, Trig, and Differential Calculus
Write e^2 = 7.389 in equivalent logarithmic form.
The base is e. The exponent is 2. The number is 7.389.
logbase(number) = exponent
loge(7.389) = 2
By convention, loge is written as ln and pronounced "lawn".
ln(7.389) = 2 is equivalent to e^2 = 7.389.
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if possible write the expressions using sums and/or difference of logarithmic expressions that do not contain the logarithms of products, quotients, or powers
1) ln(x(7-x)^3) = L
Apply Product Rule of Logarithms:
L = ln(x) + ln((7-x)^3)
Apply Power Rule of Logarithms:
L = ln(x) + 3*ln(7-x)
2) ln(xy^2/z) = L
Apply Quotient Rule of Logarithms:
L = ln(xy^2) – ln(z)
Apply Product Rule of Logarithms:
L = ln(x) + ln(y^2) – ln(z)
Apply Power Rule of Logarithms:
L = ln(x) + 2*ln(y) – ln(z)
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Elana G.
03/11/14