Dr Gulshan S. answered 03/05/17
Tutor
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Experienced Physics Tutor with a PhD
Hi Lindsey
Let D = Depth
is given by
D = 1/2 gt2
let this time be t1 = sqrt 2D/ g
let t2 = time taken by sound to travel up
t2 = D/ speed of sound = D /340
Total time = t1 +t2 =0.5 sec
2D/9.8 = 0.5*0.5 + D2/( 340*340) - 2 *0.5*D /340
Solve it for D
It could be simple equation if time taken by sound is ignored and only t1 needs to be calculated but the Depth will be just over 1m