
Arturo O. answered 02/26/17
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You can use the infinite power series expansion of sin x.
sin x = x - x3/3! + x5/5! - x7/7! + ...
where x is in radians. If x is very small (x << 1 radian), you get a good approximation for sin x from
sin x ≅ x
(By the way, this approximation is used frequently in optics and quantum physics.)
In this problem, x = 1° = 1°(π/180) radians ≅ 0.017453292
sin(1º) ≅ 0.017452406
Note x and sin x are close for this very small value of x. If x is not very small, just include more terms from the series.