could some one help me with this pre-calc question please ? Logarithms and their properties

Assuming this:

sqrt (e^9t) =e^t

(e^9t)^(1/2) =e^t

e^(9t/2) =e^t

9t/2 = t

9t/2 - t = 0

7t/2 = 0

t = 0

could some one help me with this pre-calc question please ? Logarithms and their properties

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Westford, MA

Assuming this:

sqrt (e^9t) =e^t

(e^9t)^(1/2) =e^t

e^(9t/2) =e^t

9t/2 = t

9t/2 - t = 0

7t/2 = 0

t = 0

Woodland Hills, CA

√e^9t = e ^t

e^(9/2)t = e^t

The = should not be there , because it is only true for t =0

ln ( e^ (9t/2) = 9t/2

ln e ^t = t

Maybe this was

√e ^ 9t = e ^3

e ^ (9t/2) = e ^3

9t/2 = 3

t = 6/9 = 2/3

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