Will B. answered 02/21/17
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Experienced & Knowledgeable Math Tutor - UGA Grad
So, if we imagine the equation for the height of the rocket we see that we have the equation for a parabola. Knowing this, we recall that parabola's have the standard form ax2+bx+c.
So,
a=(-16)
b=480
c=0
We may also recall that the x-coordinate (t in our case) for the vertex of a parabola occurs at (-b)/(2a) ==> (-480)/(-32)=15. So our vertex occurs at t=15s.
The height at this time is h(15)=480(15)-16(15)2 ==> h(15)=7200-3600
So h(15)=3600ft which is the highest point of the rocket's travel.