Solve for b

Question

(B+2)(b-3)=-6 solve for b 

Answer 1

Hi Lila;

(B+2)(b-3)=-6

I am assuming that B and b are the same and this is just a typographical error.

(b+2)(b-3)=-6

Let's FOIL...

FIRST...(b)(b)=b²

OUTER...(b)(-3)=-3b

INNER...(2)(b)=2b

LAST...(2)(-3)=-6

b²-3b+2b-6=-6

b²-b-6=-6

Let's add 6 to both sides...

b²-b-6+6=-6+6

b²-b=0

b(b-1)=0

b=0, and/or (b-1)=0, b=1.

 

Let's check our work...

b=0

(b+2)(b-3)=-6

(0+2)(0-3)=-6

(2)(-3)=-6

-6=-6

 

b=1

(1+2)(1-3)=-6

(3)(-2)=-6

-6=-6

Answer 2

is the B different than b or are those the same variable. if they are then you would expand the equation to b^2 + b -6 = -6 then solve for b which would give you 0 and 1. if they are not the same then you would need to move things around and get -6/(B+2) + 3= b.