16a

^{2}+56ab+49b^{2}-
CREATE FREE ACCOUNT Access thousands of free resources from expert tutorsComment on posts and interact with the authorsAsk questions and get free answers from tutorsView videos, take interactive quizzes, and more!
- Become a Student
- Become a Student
- Sign In

16a^{2}+56ab+49b^{2}

Tutors, please sign in to answer this question.

Hi Lila;

16a^{2}+56ab+49b^{2}

The numbers 16 and 49 can be square rooted into 4 and 7. When we multiply these numbers together, and then double the result, (4)(7)(2), we get 56, the coefficient of ab.

(4a+7b)(4a+7b)

Let's FOIL...

FIRST...(4a)(4a)=16a^{2}

OUTER...(4a)(7b)=28ab

INNER...(7b)(4a)=28ab

LAST...(7b)(7b)=49b^{2}

16a^{2}+28ab+28ab+49b^{2}

16a^{2}+56ab+49b^{2}

16a^2 + 56ab + 49b^2

(4a + 7b)(4a + 7b)

Meeraj P.

99th percentile SAT/AP/GRE tutor w/8+ years of experience and results

Edison, NJ

4.9
(293 ratings)

Michael K.

Effective Physics, Comp Sci, Math Tutor for HS and College Students

Staten Island, NY

4.9
(141 ratings)

Yayoi K.

Top Rated MCAT, DAT, Biology, Chemistry and Physics Tutor

East Brunswick, NJ

4.9
(37 ratings)