16a

^{2}+56ab+49b^{2}16a^{2}+56ab+49b^{2}

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Middletown, CT

Hi Lila;

16a^{2}+56ab+49b^{2}

The numbers 16 and 49 can be square rooted into 4 and 7. When we multiply these numbers together, and then double the result, (4)(7)(2), we get 56, the coefficient of ab.

(4a+7b)(4a+7b)

Let's FOIL...

FIRST...(4a)(4a)=16a^{2}

OUTER...(4a)(7b)=28ab

INNER...(7b)(4a)=28ab

LAST...(7b)(7b)=49b^{2}

16a^{2}+28ab+28ab+49b^{2}

16a^{2}+56ab+49b^{2}

Sarasota, FL

16a^2 + 56ab + 49b^2

(4a + 7b)(4a + 7b)

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