16a

^{2}+56ab+49b^{2}-
CREATE FREE ACCOUNT
- Access thousands of free resources from expert tutors
- Comment on posts and interact with the authors
- Ask questions and get free answers from tutors
- View videos, take interactive quizzes, and more!

- Become a Student
- Become a Student
- Sign In

16a^{2}+56ab+49b^{2}

Tutors, please sign in to answer this question.

Hi Lila;

16a^{2}+56ab+49b^{2}

The numbers 16 and 49 can be square rooted into 4 and 7. When we multiply these numbers together, and then double the result, (4)(7)(2), we get 56, the coefficient of ab.

(4a+7b)(4a+7b)

Let's FOIL...

FIRST...(4a)(4a)=16a^{2}

OUTER...(4a)(7b)=28ab

INNER...(7b)(4a)=28ab

LAST...(7b)(7b)=49b^{2}

16a^{2}+28ab+28ab+49b^{2}

16a^{2}+56ab+49b^{2}

16a^2 + 56ab + 49b^2

(4a + 7b)(4a + 7b)

Su H.

Patient tutor with a passion for helping students online.

Arlington, VA

4.7
(123 ratings)

Elizabeth R.

Tutor Math from elementary to high school

Woodbridge, VA

4.9
(53 ratings)

Alex S.

Retired, Looking to Share My Love of Mathematics and Computers

Fairfax Station, VA

4.9
(64 ratings)