The height of a triangle is 16 inches greater than 8 times the length of its base. If the are of the triangle is 60in^2 what is the length of the base in inches

Question

Word problem I can not figure out

Answer 1

b=base

8b+16=height

A=(1/2)(b)(h)

60=(1/2)(b)(8b+16)

120=(b)(8b16)

120=8b^2+16b

8b^2+16b-120=0

divide all terms by 8

b^2+2b-15=0

factor

(b+5)(b-3)=0

b-3=0

b=3 inches (answer)

h=8*3+16=40 inches