Mark M. answered 02/12/17
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Retired college math professor. Extensive tutoring experience.
Let y = 4x3+5
Switch x and y: x = 4y3+5
Solve for y: 4y3 = x-5
y3 = (x-5)/4 So, y = [(x-5)/4]1/3
G-1(x) = [(x-5)/4]1/3
Verification: Show that G(G-1(x)) = G-1(G(x))=x
G(G-1(x)) = G([(x-5)/4]1/3) = 4([(x-5)/4]1/3)3 + 5
= 4([(x-5)/4]) + 5 = x-5+5 = x
G-1(G(x)) = G-1(4x3+5) = [(4x3+5-5)/4]1/3
= [4x3/4]1/3 = [x3]1/3 = x