HELP!! NEED THIS SOLVED

Question

1/6=1/3x^2+1/2x

 

Answer 1

1/6 = 1/3x^2 + 1/2x

 

multiply by 6x^2 on both sides of the equation to get rid of fractions and negative exponents

 

x^2 = 2 + 3x

 

x^2 - 3x - 2 = 0 (rearranging)

 

using the quadratic formula; x = [-b +-(b^2 - 4*a*c)^1/2]/2*a 

 

for this equation a = 1; b = -3; and c = -2 (coefficients)

 

x = [3 +-(9+8)^1/2]/2*1 = (3+-4.12)/2 

 

Answer x = (3 + 4.12)/2 = 3.56, or (3 - 4.12)/2 = -0.56

Answer 2

1/6=(1/3x^2)+(1/2x)

multiply both sides by the LCM of the three denominators which is 6x^2

you get...

x^2=2+3x

x^2-3x-2=0

use the quadratic equation

[3±√(9+8)]/2

[3±√(17)]/2

x=(3+√17)/2 and

x=(3-√17)/2