How much did she invest at each rate?

Question

Jolene invests her savings in two bank accounts, one paying 3 percent and the other paying 10 percent simple interest per year. She puts twice as much in the lower-yielding account because it is less risky. Her annual interest is 4592 dollars.

 

Amount invested at 3 percent interest is $

Amount invested at 10 percent interest is $

Answer 1

This type of problem recurs over and over in these questions. The idea is to express the words in terms of equations. Here is a simple example:

Jack invests $1,000 is two investments, one yielding 5% per year and the other yielding 7% per year. At the end of one year he earned $63 of interest. How much was invested in each account?.

Let A = the account that earns 5% and B the account that earns 7%

A + B = 1,000
and
.05A + .07B = 63

Now express A in terms of B in the first equation and substitute in the second equation.
A = 1,000 – B
.05*(1,000 – B) + .07B = 63

50 – .05B + .07B = 63
.02B = 13
B = 13 / .02 = 650

Now that you know B you can use the fist equation to find A. Use A and B in the second equation to prove that the total amount of interest earned is 63.

In your problem the first equation is

 

2A = B

 

Now follow the above example and solve the problem.