a bicycle wheel rotate 5 times. the bicycle travels 37.94 feet in inches what is the diameter. using 3.14 for pie

Question

a bicycle wheel rotates 5 times. The bicycle travels 37.94 feet in inches what is the  diameter. Using 3.14 for pie.

 

Answer 1

Hi Ximena;

(37.94 feet)/(5 rotations)=7.588 feet

7.588 feet is the perimeter of the tire.

perimeter=(diameter)(3.14)

(7.588 feet)[(12 inch)/(1 foot)]=(diameter)(3.14)

The unit of feet/foot is in the numerator and denominator.  It cancels...

(7.588 feet)[(12 inch)/(1 foot)]=(diameter)(3.14)

(7.588)(12 inch)=(diameter)(3.14)

91.056 inches=(diameter)(3.14)

Divide both sides by 3.14...

(91.056 inches)/(3.14)=[(diameter)(3.14)]/(3.14)

29. inches=diameter

 

 

Answer 2

(5 rotations)(pi D inches / rotation)(1 foot/12 inches) = 37.94 feet

 

D = 37.94 * 12 / (5 * 3.14) inches

 

D = 28.99872611464968 inches = 29 inches

Answer 3

37.94ft/ 5 = 7.59 ft

 

 d∏ = 7.59 ft

 

  d = 2.42 ft

Answer 4

If the bicycle wheel rotates 5 times and travels 37.94 feet, then we know that the circumference of the wheel (the outside of the wheel as it touches the ground 5 times around) is 37.94/5 = 7.588

 

Then we use the formula for the circumference of a circle: 2(pi)(radius) = circumference

 

We plug in what we know 2(3.14)(radius) = 7.588 and then solve for the radius

 

We divide 2 from both sides of the equation (3.14)(radius) = 3.794

 

We divide pi from both sides (radius) = 1.208

 

Then the last step, we multiply the radius by 2, because we need the diameter, which is double the radius

 

1.208 * 2 = 2.416 or 2.42 rounded up

 

Final answer = 2.42 feet

Answer 5

The distance traveled in one rotation of the wheel is equal to the circumference, pi*diameter.  So, after five rotations, the distance is 5*3.14*diameter= 37 feet = 444 inches; tre diameter is 444 inches/(5*3.14) =

28.2 inches

Answer 6

Hi Ximena,

 

First there are two relationships/equations needed in this problem. N is 5 (#of cycles)

 

1) C=π*D

where C is the circumference

          π is pi (3.14)

          D is diameter of the wheel

 

2) L=N*C

where L is the length traveled

         N is the number of cycles

         C is the circumference

 

So the problem asks us to find the diameter of the wheel in inches.

 

L=37.94ft

  =37.94 ft * (12in/1ft)

  =455.28 inches

 

take equation (1) and (2) and combine them

 

L=5*C-->

L=5*(π*D)

substitute 455.28 for L and 3.14 for π...

 

455.28=5*3.14*D

 

Solve for D...

 

455.28/(5*3.14)=D

 

D=28.998 inches --> D= 29 inches

Answer 7

37.94/5 = 7.588 feet = 3.14 * Diameter,

Diameter = 7.588/3.14 * 12 = 28.999, so 29 inches 

Answer 8

Distance traveled by wheel in one rotation - circumference of the wheel - 2 x pi x radius = 2 x 3.14 x r

 

Distance traveled in five times rotation = 5 x 2 x 3.14 x r = 37.94

 

divide both sides by 5, 2 and 3.14

 

r = 37.94/(5 x 2 x 3.14) = 1.2 feet = 14.5 inches