Gregg K. answered 12/15/16
Tutor
5.0
(393)
Effective Math Tutor Specializing in AP Calculus AB/BC , AP Statistics
Sounds like a system of 3 equations with 3 unknowns
K + L + M = 73
2K = L + 3M - 11
6M + 2 = K + 3L
K + L + M = 73 EQ1
2K - L - 3M = -11 EQ 2
-K -3L + 6M = -2 EQ 3
Let's reduce this to two variables by eliminating L
Add EQ1 with EQ2
3K - 2M = 62 EQ4
Now triple EQ1 and add to EQ3
2K + 9M = 217 EQ5
So now we have 2 unknowns
3K - 2M = 62 EQ4
2K + 9M = 217 EQ5
Double EQ4 and Triple EQ5 and subtract
31M = 527
divide by 31, M = 17
sub M = 17 back into EQ 4
3K -34 = 62
3K = 96
K = 32
NOW sub M = 17 and K = 32 back into EQ1
32 + L + 17 = 73
49 + L = 73
L = 24