Gregg K. answered • 12/06/16
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There is no solving here. Are we just to write the function f(x) in vertex form. The question is unclear when the directions state solve by completing the square.
Now if the problem stated solve 12 = 6x^2-49x +8 then saying solve would make more sense.
Let me know what you really want done and I will show you how.
By the way, I just used 12 as any arbitrary number.
Are you looking for the roots of the function?
Alissa G.
and where you have a 12 would be a zero
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12/06/16
Michael J.
I showed you how to solve it with the square-root thing that you speak of. Did you read my answer?
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12/06/16
Alissa G.
I know but it doesnt seem right because i did the quadratic formula way and they arent the same...
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12/06/16
Michael J.
Somewhere down the road, you must have made a minor error in your algebra.
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12/06/16
Michael J.
I stand corrected. I made a minor error. In the step where you add the squared value to both sides of equation, I added 2401/144 on the left side. But the right side, I added 2401/44. This was the part that messed you up. Somehow, I missed the 1 key on my keyboard when adding it to the right side. The denominator was supposed to be 144, and not 44. But I corrected it here.
x2 - (49/6)x + (2401/144) = (2401/144) - (4/3)
(x - (49/12))2 = (2401/144) - (4/3)
(x - (49/12))2 = (2401/144) - (4/3)
Now you can continue from here.
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12/06/16
Alissa G.
I had 12 as my overall denomenator tho
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12/06/16
Alissa G.
What is your final answer?
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12/06/16
Alissa G.
12/06/16