This is a linear programming problem, where we want to maximize storage space while staying within the budget and available floor space.
Step 1: Define the variables.
Let:
- x = number of Model X cabinets
- y = number of Model Y cabinets
We know:
Model X:
- Costs $10
- Uses 6 square feet of floor space
- Holds 8 cubic feet of files
Model Y:
- Costs $20
- Uses 8 square feet of floor space
- Holds 12 cubic feet of files
Step 2: Write the constraints.
Budget constraint:
10x + 20y ≤ 140
Divide by 10:
x + 2y ≤ 14
Floor space constraint:
6x + 8y ≤ 72
Divide by 2:
3x + 4y ≤ 36
We also know:
x ≥ 0 and y ≥ 0
Both variables must be whole numbers because we cannot purchase fractions of cabinets.
Step 3: Write the objective function.
We want to maximize the total storage volume.
V = 8x + 12y
Step 4: Find the corner points of the feasible region.
The maximum value of a linear objective function occurs at a corner point of the feasible region.
First, find the intercepts of the constraints.
For the budget constraint:
x + 2y = 14
Intercepts: (14, 0) and (0, 7)
For the floor space constraint:
3x + 4y = 36
Intercepts: (12, 0) and (0, 9)
The feasible region is in the first quadrant and below both lines.
Its corner points are:
(0, 0), (12, 0), (8, 3), and (0, 7).
To find the intersection (8, 3), solve the two equations together:
x + 2y = 14
3x + 4y = 36
Multiply the first equation by 3:
3x + 6y = 42
Subtract the second equation:
2y = 6
y = 3
Substitute back:
x + 2(3) = 14
x = 8
Step 5: Evaluate the objective function at each corner point.
V = 8x + 12y
At (0, 0):
V = 0
At (12, 0):
V = 8(12) = 96 cubic feet
At (8, 3):
V = 8(8) + 12(3)
V = 64 + 36 = 100 cubic feet
At (0, 7):
V = 12(7) = 84 cubic feet
The greatest storage volume is 100 cubic feet.
Step 6: Verify the constraints.
Buying 8 Model X cabinets and 3 Model Y cabinets:
Total cost:
10(8) + 20(3) = $140
Total floor space:
6(8) + 8(3) = 72 square feet
Both constraints are satisfied exactly!
Final Answer: Buy 8 Model X cabinets and 3 Model Y cabinets.
This combination provides a maximum storage capacity of 100 cubic feet, uses exactly 72 square feet of floor space, and costs exactly $140.
Since both quantities are whole numbers, the solution is practical and does not require any rounding.