Inactive Tutor answered 12/02/16
Tutor
New to Wyzant
For all to be defective, the # ways to get this is 44C44, which is 1 (obviously--there's only one way to get them all).
The denominator 1010C44 is # ways to choose 44 transistors from the whole box.
The probability of all defective is 1/(1010C44). Use your calculator!to compute this tiny result.
The probability that NONE are defective is 1 minus the above (tiny) result.