
Kenneth S. answered 12/02/16
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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
For all to be defective, the # ways to get this is 44C44, which is 1 (obviously--there's only one way to get them all).
The denominator 1010C44 is # ways to choose 44 transistors from the whole box.
The probability of all defective is 1/(1010C44). Use your calculator!to compute this tiny result.
The probability that NONE are defective is 1 minus the above (tiny) result.