Hi Andrew
Interesting problem that requires 2 equations
You have 2 variables X and Y.
You know that X - Y = 3 and you know that Y2 = 4X
If you solve the first problem for X in terms of Y it leaves you with X = 3 + Y and you can substitute that in the second equation:
Y2 = 4(3+Y)
Now distribute
Y2 = 12 + 4Y
then rearrange your equation to look like a standard polynomial to factor it:
Y2 - 4Y - 12
factoring gives us
(Y+2) and (Y-6)
Y=6 is a great answer because it means X = 9 and 9-6 = 3 so that first equation works and 62 = 36 and 4(9) = 36 so the second equation works.
All the best,
Lori