This is a system of equations problem.
Let G = the number of general admission tickets and S = the number of student ID tickets.
G + S = 182 Total tickets.
3G + 2S = 438 Total price paid for tickets.
Solution by substitution is easier for this one.
Solve one of the equations for either G or S in terms of the other, then substitute that into the other equation.
G + S = 182
S = 182 - G
3G + 2S = 438
3G + 2 * (182 - G)= 438
3G + 364 -2G = 438
G = 438 - 364 = 74 General admission tickets
Substitute this into either equation and solve for S.
We already solved one for S symbolically, so we'll use that.
S = 182 - G
S = 182 - 74 = 108 Student ID tickets