This is a system of equations problem.

Let G = the number of general admission tickets and S = the number of student ID tickets.

G + S = 182 Total tickets.

3G + 2S = 438 Total price paid for tickets.

Solution by substitution is easier for this one.

Solve one of the equations for either G or S in terms of the other, then substitute that into the other equation.

G + S = 182

S = 182 - G

3G + 2S = 438

3G + 2 * (182 - G)= 438

3G + 364 -2G = 438

G = 438 - 364 = 74 General admission tickets

Substitute this into either equation and solve for S.

We already solved one for S symbolically, so we'll use that.

S = 182 - G

S = 182 - 74 = 108 Student ID tickets