
Al P. answered 11/22/16
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Let:
a = first number
b = second number
a = b+2 ("two more than second number")
4a = 5b-1 ("Four times first is one less than 5 times second")
We have two equations and two unknowns. One easy approach from here is to notice that the top equation allows us to substitute "b+2" for "a" in the 2nd equation:
4a = 5b-1 (re-wrote 2nd equation)
4(b+2) = 5b-1 (substituted "b+2" for "a")
4b+8 = 5b-1 (multiplied 4 into paren's)
4b+9 = 5b (added 1 to both sides)
9 = b (subtracted 4b from both sides)
b=9 —> a=11 (from 1st eqn)
Ans: the two numbers are 9 and 11.
Check:
4*(11) = 44
5*(9)-1 = 44 (ok)
and 11 is two more than 9 (ok)