
Amarjeet K. answered 02/06/14
Tutor
4.6
(8)
Professional Engineer for Math and Science Turoring
Let wts of 5 boys be x1, x2, x3, x4, x5
x1 + x2 = 90
x1 + x3 = 92
x1 + x4 = 93
x1 + x5 = 94
x2 + x3 = 95
x2 + x4 = 96
x2 + x5 = 97
x3 + x4 = 98
x3 + x5 = 100
X4 + x5 = 101
Add all equations
4x1 + 4x2 + 4x3 + 4x4 + 4x5 = 956
Divide both sided by 4
x1 + x2 + x3 + x4 + x5 = 239 = wt of five boys
:)
Taneque H.
02/12/14