Virus cell growth

Question

The growth formula of virus cells is given as N=100(2)^0.17t, where N is the number of virus cells present after (t) days. Calculate the number of days, to the nearest hour, taken for the bacteria to double. 

 

 

Answer 1

When the bacteria doubles, the amount will be

 

2N

 

 

So you have the equation

 

2N = 100(2)^0.17t

 

 

Log both sides of the equation bring the exponents as the coefficient of the log.

 

Log(2N) = 0.17tLog(200)

 

 

Divide both sides of the equation by 0.17Log(200).

 

Log(2N) / 0.17Log(200) = t

 

 

Also, use the conversion factor.

 

1 day = 24 hours