John M. answered 10/23/17
Tutor
4.9
(96)
H.S. Chemistry, A.P. Chem, Physical Science and College Freshman Chem
Knowing the rate law, you can plug in hypothetical values and see what happens. For example, since you're doubling the concentration of A and tripling that of B, you could do this:
k[2][3]^2 = 18. So the rate would be 18 times faster. Thus, the appearance of C would be 18 times faster than if the concentrations of A & B were equal to one.