three consecutive integers are such that three times the smallest is 18 more than the largest

Question

i have to find three consecutive integers are such that three times the smallest is 18 more than the largest. 

Answer 1

Suppose 3 consecutive integers are x, x+1, x+2

 

smallest is x, largest is x+2

 

3x= x+2 +18

 

2x= 20

x=10

 

Three consecutive integers are, 10, 11, 12

 

Check: smallest number=10

                      3 times smallest  = 30 which is 18 more than largest number 12.