f'(x) = (1-x)(2-x)
f''(x) = 2x - 3
The extreme points (maxima and minima) occur where f'(x) = 0, which occurs when x = 1 and x = 2. At x = 1, f''(x) = 2(1)-3 = -1, so f(x) has a maximum at x=1. f''(2) = 2(2)-3 = 1, so f(x) has a minimum at x = 2. Hence:
- f(x) is increasing on the interval (-∞,1)
- f(x) is decreasing on the interval (1,2)
- f(x) is increasing on the interval (2,∞)
Note: f(x) = (1/3)x3 - (3/2)x2 + 2x