
Kenneth S. answered 10/24/16
Tutor
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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
f (θ) = 2sec θ + tanθ
f' = 2sec θ tanθ + sec2θ = sec θ (2tan θ + sec θ) = 0 at critical points.
The first factor is never 0.
Now we have to solve (2tan θ + sec θ) = 0 or 2 sin θ / cos θ + 1/cos θ = 0.
2 sin θ = -1 sin θ = -½.
θ = 14pi + 7pi/6 or 14pi + 11pi/6