For the function g(x) = (1/16)^x Find the function value at g(- 3/2)

Question

For the function g(x)=(1/16)^x

 

Find the function value at g(- 3/2) this problem is g  - minus 3/2

 

g(- 3/2) = ?

Answer 1

g(x) = (1/16)^x

g(-3/2) = (1/16)^-3/2

g(-3/2) = (1/4)^-3           take square root (1/2 power)

g(-3/2) = 4³                 convert to positive exponent

g(-3/2) = 64