
Norbert W. answered 10/20/16
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Let w be the uniform width for the border.
Including the garden the dimensions of the garden and border would be (12 + 2w) by (26 + 2w), which is an area
A = (12 + 2w) * (26 + 2w) = 312 + 24w + 52 w + 4w2 = 4w2 + 76w + 312
Subtracting the area of the garden leaves the area for the grass border to be (4w2 + 76w) which is the same as the
amount seed to cover 264 square feet.
4w2 + 76w = 264
Dividing through by 4 this is the same as w2 + 19w -66 = 0
Now w2 + 19w - 66 = (w - 3) * (w + 22 ) = 0
The border must be 3 feet wide. The other solution is -22 which is negative and can not be the value for the border.