Kenneth S. answered • 10/18/16
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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
from term#9 to term #10 (from -24 to -30), it's obvious that the constant difference d = -6 is added.
to proceed on to the 30th term (from 10th), one must take 20 steps, so a30 = -30 + (20)(-6) = -150
The above line has been corrected because of a misreading, in which I aimed for ten terms beyond the given #10.
This error requires me to revise some of my comments, but I do not see a way to revise THEM.
Reader BEWARE!
Crystal M.
How do you find a1?
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10/18/16
Kenneth S.
BACK UP 8 steps from a9. You'll be subtracting 8 times negative 6, which amounts to adding 48.
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10/18/16
Andrew M.
We are going from the 10th term to the 30th term:
With the difference d=-6
we go 20 steps to get from the 10th term to the 30th.
-30 + 20(-6) = -30 -120 = -150
The 30th term is -150
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10/19/16
Crystal M.
10/18/16