Jason L. answered 10/14/16
Tutor
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Graduate Student Who Loves to Do Math
You need the hypergeometric distribution to solve these, which is simply a proportion of the combinations of your sample (the 5 numbers you choose) and population (all 49 numbers available to be chosen).
P(all 5 numbers get picked) = 5C5 * 44C0 / 49C5
(This is saying the total combinations in which all 5 numbers n the card are chosen times the combinations in which the 44 other numbers are not chosen divided by all possible combinations of 5 numbers from the population of 49)
P (4/5 numbers get picked) = 5C4 * 44C1 / 49C5
P(0,1,2, or 3 numbers get picked) = 1 - P(5 picked) - P(4 picked)
A fast check your work on these is using the hypgeom.dist function in Excel. The first one would be =hypgeom.dist(5,5,5,49,FALSE), etc.