write the equation y=3x+8 through (6,5)

Question

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Answer 1

The line y=3x+8 has a slope of 3.

 

All lines that are perpendicular to it have a slope that is the negative reciprocal of 3 [that is, (-1/3)].

 

So, the formula for those lines looks like y=(-1/3)x + b and we need a point like (6,5) to find b.

      5 = (-1/3)(6) + b

      5 = -2 + b

      7 = b

 

The equation of this perpendicular line is:   y=(-1/3)x + 7

Answer 2

The line given by y = 3x + 8 DOES NOT pass through the point (6,5).  Test it:

 

y = 3x + 8 = 3(6) + 8 = 26 ≠ 5