
Machelle P.
asked 01/26/14Find the distance p1= [-1,3] p2=[4,4]
Find the distanced (P1P2) between the given points p1 and p2
p1 (-1,3)
P2=(4,4)
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3 Answers By Expert Tutors

Vivian L. answered 01/26/14
Tutor
3
(1)
Microsoft Word/Excel/Outlook, essay composition, math; I LOVE TO TEACH
Hi Machelle;
p1= [-1,3] p2=[4,4]
This is a triangle.
One side of the triangle is the distance between the values of y...
y-y1
4-3=1
Another side of the triangle is the distance between the values of x...
x-x1
4--1
Subtracting a negative number is the same as adding a positive number...
4+1=5
Pythagorean Theorem...
a2+b2=c2
a and b are the sides of established lengths 1 and 5.
c is the hypotenuse. This is the length were are looking for.
12+52=c2
1+25=c2
26=c2
√26=c
The distance formula is
d=√(x2-x1)2+(y2-y1)2
p1=(x1,y1)=(-1,3)
p2=(x2,y2)=(4,4)
d=√(4-(-1))2+(4-3)2
=√25+1
=√26

Curt J. answered 01/26/14
Tutor
5
(8)
Math/Science/General Ed Tutor in West Honolulu
Hi Machelle,
This problem utilizes what is known as the distance formula:
d=√[(x2-x1)2+(y2-y1)2]
Where p1=(x1,y1) and p2=(x2,y2)
Using this info, you should be able to solve. Give me a moment and I can provide a more detailed explanation for WHY this distance formula works.
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Curt J.
01/26/14