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Question

A waitress sold 13

ribeye steak dinners and 38

grilled salmon? dinners, totaling ?$550.63

on a particular day. Another day she sold 27

ribeye steak dinners and 19

grilled salmon? dinners, totaling ?$581.16
.
How much did each type of dinner? cost?

Answer 1

Let x = cost of ribeye dinners

 

y = cost of salmon dinners

 

13x + 38y = 550.63

27x + 19y = 581.16

 

Using the Elimination Method, we can multiply the bottom equation by 2 and subtract the two linear equations from each other:

 

13x + 38y = 550.63

54x + 38y = 1162.32

 

Subtracting gives us

 

-41x = -611.69

x = $14.92 = cost of ribeye dinners

 

You can substitute this value of x into either of the two original linear equations in order to determine the cost of salmon dinners