The sum of three numbers is 151. The third number is 4 times the first. The second number is 7 more than the first. What are the numbers?

Question

The sum of three numbers is 151. The third number is 4 times the first. The second number is 7 more than the first. What are the numbers?

Answer 1

Hey Shell,

 

let  first number = x

 

second number = x + 7

 

Third number = 4x

 

sum of the three numbers = 6x + 7

 

6x + 7 = 151

 

6x = 144

 

x = 24

 

first number is 24, second number is 31 and the third number is 96.

 

Hope this helps.

 

Mayuran

Answer 2

Here's what we know:

a + b + c = 151 (the sum of the three is 151)

c = 4a (the third # is 4 times the first)

b = a + 7 (the second is 7 more than the first)

 

Now we plug in the variable values:

a + a + 7 + 4a = 151

Simplify:

6a + 7 = 151

Subtract 7:

6a = 144

Divide by 6:

a = 24

 

b = 24 + 7

b = 31

 

c = 4 * 24

c = 96

 

Check:

24 + 31 + 96 = 151

151 = 151

Answer 3

set your first number equal to  x.  your other two numbers are variations of x  (4x and x+7).  When you add all three together they equal 151.  

 

solve for x. that's the first number

now do 4x equals your second number

7+x equals your third number