Operation with Functions- g(n)=n-2, f(n)=n^2-3-n Find (-2g+3f)(n)

Question

Please help guide me through this. I don't even know the first step. 

Answer 1

g(n) = n - 2

-2g(n) = -2(n - 2)

-2g(n) = -2n + 4

 

f(n) = n² - 3 - n

3f(n) = 3(n² - 3 - n)

3f(n) = 3n² - 9 - 3n

 

(-2g + 3f)(n) = (-2n + 4) + (3n² - 9 - 3n)

 

Can you simplify?